Base | Representation |
---|---|
bin | 10010011011101100… |
… | …11001011011010111 |
3 | 221112200010221000121 |
4 | 21031312121123113 |
5 | 130231341241101 |
6 | 4313550252411 |
7 | 500142645004 |
oct | 111566313327 |
9 | 27480127017 |
10 | 9896040151 |
11 | 4219069488 |
12 | 1b021b7107 |
13 | c192bb47a |
14 | 69c4208ab |
15 | 3cdbc50a1 |
hex | 24dd996d7 |
9896040151 has 2 divisors, whose sum is σ = 9896040152. Its totient is φ = 9896040150.
The previous prime is 9896040109. The next prime is 9896040211. The reversal of 9896040151 is 1510406989.
9896040151 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 9896040151 - 27 = 9896040023 is a prime.
It is a super-3 number, since 3×98960401513 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 9896040098 and 9896040107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (9896040101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4948020075 + 4948020076.
It is an arithmetic number, because the mean of its divisors is an integer number (4948020076).
Almost surely, 29896040151 is an apocalyptic number.
9896040151 is a deficient number, since it is larger than the sum of its proper divisors (1).
9896040151 is an equidigital number, since it uses as much as digits as its factorization.
9896040151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 77760, while the sum is 43.
The square root of 9896040151 is about 99478.8427305022. The cubic root of 9896040151 is about 2146.9428445348.
The spelling of 9896040151 in words is "nine billion, eight hundred ninety-six million, forty thousand, one hundred fifty-one".
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