Search a number
-
+
99000096000133 is a prime number
BaseRepresentation
bin10110100000101001000001…
…100011100000100010000101
3110222112022112220112102020011
4112200221001203200202011
5100434004144034001013
6550320003301510221
726565343445316046
oct2640510143404205
9428468486472204
1099000096000133
11295a97832a0639
12b12aa6ba12371
134331890a20423
141a638b74388cd
15b6a3466bcc3d
hex5a0a418e0885

99000096000133 has 2 divisors, whose sum is σ = 99000096000134. Its totient is φ = 99000096000132.

The previous prime is 99000096000031. The next prime is 99000096000149. The reversal of 99000096000133 is 33100069000099.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 76853678824129 + 22146417176004 = 8766623^2 + 4705998^2 .

It is an emirp because it is prime and its reverse (33100069000099) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 99000096000133 - 29 = 99000095999621 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (99000096000163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49500048000066 + 49500048000067.

It is an arithmetic number, because the mean of its divisors is an integer number (49500048000067).

Almost surely, 299000096000133 is an apocalyptic number.

It is an amenable number.

99000096000133 is a deficient number, since it is larger than the sum of its proper divisors (1).

99000096000133 is an equidigital number, since it uses as much as digits as its factorization.

99000096000133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 39366, while the sum is 40.

The spelling of 99000096000133 in words is "ninety-nine trillion, ninety-six million, one hundred thirty-three", and thus it is an aban number.