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99004311340147 is a prime number
BaseRepresentation
bin10110100000101100111100…
…110011110000010001110011
3110222112201102200102212122101
4112200230330303300101303
5100434041312200341042
6550321541443121231
726565553062160063
oct2640547463602163
9428481380385571
1099004311340147
1129600546794a14
12b12b847673217
1343320b313a465
141a63b972053a3
15b6a4e17cc6b7
hex5a0b3ccf0473

99004311340147 has 2 divisors, whose sum is σ = 99004311340148. Its totient is φ = 99004311340146.

The previous prime is 99004311340087. The next prime is 99004311340177. The reversal of 99004311340147 is 74104311340099.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 99004311340147 - 227 = 99004177122419 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 99004311340097 and 99004311340106.

It is not a weakly prime, because it can be changed into another prime (99004311340177) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49502155670073 + 49502155670074.

It is an arithmetic number, because the mean of its divisors is an integer number (49502155670074).

Almost surely, 299004311340147 is an apocalyptic number.

99004311340147 is a deficient number, since it is larger than the sum of its proper divisors (1).

99004311340147 is an equidigital number, since it uses as much as digits as its factorization.

99004311340147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 326592, while the sum is 46.

The spelling of 99004311340147 in words is "ninety-nine trillion, four billion, three hundred eleven million, three hundred forty thousand, one hundred forty-seven".