Base | Representation |
---|---|
bin | 101110000110101110… |
… | …1100011111110000001 |
3 | 100110120011222021021021 |
4 | 1130031131203332001 |
5 | 3110233041213441 |
6 | 113252402025441 |
7 | 10103363654641 |
oct | 1341535437601 |
9 | 313504867237 |
10 | 99010101121 |
11 | 38a98691458 |
12 | 17232348281 |
13 | 944b6cb169 |
14 | 4b137c2521 |
15 | 28973a13d1 |
hex | 170d763f81 |
99010101121 has 2 divisors, whose sum is σ = 99010101122. Its totient is φ = 99010101120.
The previous prime is 99010101109. The next prime is 99010101139. The reversal of 99010101121 is 12110101099.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 50922435600 + 48087665521 = 225660^2 + 219289^2 .
It is an emirp because it is prime and its reverse (12110101099) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 99010101121 - 25 = 99010101089 is a prime.
It is not a weakly prime, because it can be changed into another prime (99010101181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49505050560 + 49505050561.
It is an arithmetic number, because the mean of its divisors is an integer number (49505050561).
Almost surely, 299010101121 is an apocalyptic number.
It is an amenable number.
99010101121 is a deficient number, since it is larger than the sum of its proper divisors (1).
99010101121 is an equidigital number, since it uses as much as digits as its factorization.
99010101121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 25.
The spelling of 99010101121 in words is "ninety-nine billion, ten million, one hundred one thousand, one hundred twenty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •