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9902552439113 is a prime number
BaseRepresentation
bin1001000000011001111000…
…0111101101100101001001
31022001200012220110020210122
42100012132013231211021
52244220411411022423
633021100401353025
72041302323631245
oct220063607554511
938050186406718
109902552439113
113178715769234
12113b220938775
1356aa643a88a9
1426340108d425
151228c4d418c8
hex9019e1ed949

9902552439113 has 2 divisors, whose sum is σ = 9902552439114. Its totient is φ = 9902552439112.

The previous prime is 9902552439097. The next prime is 9902552439163. The reversal of 9902552439113 is 3119342552099.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9856033282624 + 46519156489 = 3139432^2 + 215683^2 .

It is a cyclic number.

It is not a de Polignac number, because 9902552439113 - 24 = 9902552439097 is a prime.

It is not a weakly prime, because it can be changed into another prime (9902552439163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4951276219556 + 4951276219557.

It is an arithmetic number, because the mean of its divisors is an integer number (4951276219557).

Almost surely, 29902552439113 is an apocalyptic number.

It is an amenable number.

9902552439113 is a deficient number, since it is larger than the sum of its proper divisors (1).

9902552439113 is an equidigital number, since it uses as much as digits as its factorization.

9902552439113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2624400, while the sum is 53.

The spelling of 9902552439113 in words is "nine trillion, nine hundred two billion, five hundred fifty-two million, four hundred thirty-nine thousand, one hundred thirteen".