Base | Representation |
---|---|
bin | 11100110100100110010… |
… | …01001010010011011011 |
3 | 10111200011111002211221021 |
4 | 32122103021022103123 |
5 | 112211124122132311 |
6 | 2034535340223311 |
7 | 131355555501415 |
oct | 16322311122333 |
9 | 3450144084837 |
10 | 990311130331 |
11 | 351a968a7796 |
12 | 13bb1923ab37 |
13 | 72502ba5373 |
14 | 35d077539b5 |
15 | 1ab60d65171 |
hex | e69324a4db |
990311130331 has 2 divisors, whose sum is σ = 990311130332. Its totient is φ = 990311130330.
The previous prime is 990311130311. The next prime is 990311130463. The reversal of 990311130331 is 133031113099.
990311130331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 990311130331 - 211 = 990311128283 is a prime.
It is a super-2 number, since 2×9903111303312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (990311130311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 495155565165 + 495155565166.
It is an arithmetic number, because the mean of its divisors is an integer number (495155565166).
Almost surely, 2990311130331 is an apocalyptic number.
990311130331 is a deficient number, since it is larger than the sum of its proper divisors (1).
990311130331 is an equidigital number, since it uses as much as digits as its factorization.
990311130331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6561, while the sum is 34.
The spelling of 990311130331 in words is "nine hundred ninety billion, three hundred eleven million, one hundred thirty thousand, three hundred thirty-one".
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