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99143110001141 is a prime number
BaseRepresentation
bin10110100010101110001101…
…110110101000000111110101
3111000000222200210121102002022
4112202232031312220013311
5100443330042130014031
6550505414352122525
726611565455263233
oct2642561566500765
9430028623542068
1099143110001141
11296543a1a382a8
12b152722b36445
134342202b5966b
141a6a7a3075953
15b6de16ceb97b
hex5a2b8dda81f5

99143110001141 has 2 divisors, whose sum is σ = 99143110001142. Its totient is φ = 99143110001140.

The previous prime is 99143110001129. The next prime is 99143110001149. The reversal of 99143110001141 is 14110001134199.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 93966365640625 + 5176744360516 = 9693625^2 + 2275246^2 .

It is an emirp because it is prime and its reverse (14110001134199) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 99143110001141 - 238 = 98868232094197 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (99143110001149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49571555000570 + 49571555000571.

It is an arithmetic number, because the mean of its divisors is an integer number (49571555000571).

Almost surely, 299143110001141 is an apocalyptic number.

It is an amenable number.

99143110001141 is a deficient number, since it is larger than the sum of its proper divisors (1).

99143110001141 is an equidigital number, since it uses as much as digits as its factorization.

99143110001141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 35.

The spelling of 99143110001141 in words is "ninety-nine trillion, one hundred forty-three billion, one hundred ten million, one thousand, one hundred forty-one".