Base | Representation |
---|---|
bin | 1001000001001000101111… |
… | …0101101001101111000011 |
3 | 1022002212200111111212210102 |
4 | 2100102023311221233003 |
5 | 2244422141414214041 |
6 | 33030540443353015 |
7 | 2042226115445162 |
oct | 220221365515703 |
9 | 38085614455712 |
10 | 9915130616771 |
11 | 3182a8a823286 |
12 | 114175122276b |
13 | 56bcba268273 |
14 | 263c757b33d9 |
15 | 122dae21e09b |
hex | 9048bd69bc3 |
9915130616771 has 2 divisors, whose sum is σ = 9915130616772. Its totient is φ = 9915130616770.
The previous prime is 9915130616749. The next prime is 9915130616773. The reversal of 9915130616771 is 1776160315199.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 9915130616771 - 242 = 5517084105667 is a prime.
It is a super-4 number, since 4×99151306167714 (a number of 53 digits) contains 4444 as substring.
Together with 9915130616773, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (9915130616773) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4957565308385 + 4957565308386.
It is an arithmetic number, because the mean of its divisors is an integer number (4957565308386).
Almost surely, 29915130616771 is an apocalyptic number.
9915130616771 is a deficient number, since it is larger than the sum of its proper divisors (1).
9915130616771 is an equidigital number, since it uses as much as digits as its factorization.
9915130616771 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2143260, while the sum is 56.
The spelling of 9915130616771 in words is "nine trillion, nine hundred fifteen billion, one hundred thirty million, six hundred sixteen thousand, seven hundred seventy-one".
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