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9920041012223 is a prime number
BaseRepresentation
bin1001000001011011000010…
…0001010100101111111111
31022010100100201021211000122
42100112300201110233333
52300012220444342343
633033112014245155
72042461602224666
oct220266041245777
938110321254018
109920041012223
11318507a59a041
1211426a17b67bb
1356c5c0682bc4
142641bd9cbddd
1512309a376068
hex905b0854bff

9920041012223 has 2 divisors, whose sum is σ = 9920041012224. Its totient is φ = 9920041012222.

The previous prime is 9920041012207. The next prime is 9920041012247. The reversal of 9920041012223 is 3222101400299.

9920041012223 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (3222101400299) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 9920041012223 - 24 = 9920041012207 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (9920041092223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4960020506111 + 4960020506112.

It is an arithmetic number, because the mean of its divisors is an integer number (4960020506112).

Almost surely, 29920041012223 is an apocalyptic number.

9920041012223 is a deficient number, since it is larger than the sum of its proper divisors (1).

9920041012223 is an equidigital number, since it uses as much as digits as its factorization.

9920041012223 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 35.

The spelling of 9920041012223 in words is "nine trillion, nine hundred twenty billion, forty-one million, twelve thousand, two hundred twenty-three".