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9921550343 is a prime number
BaseRepresentation
bin10010011110101111…
…01101100000000111
3221121110010222102112
421033113231200013
5130304404102333
64320301131235
7500602533515
oct111727554007
927543128375
109921550343
114231502691
121b0a859b1b
13c21680963
146a19814b5
153d1063948
hex24f5ed807

9921550343 has 2 divisors, whose sum is σ = 9921550344. Its totient is φ = 9921550342.

The previous prime is 9921550297. The next prime is 9921550349. The reversal of 9921550343 is 3430551299.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 9921550343 - 232 = 5626583047 is a prime.

It is a super-2 number, since 2×99215503432 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 9921550343.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (9921550349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4960775171 + 4960775172.

It is an arithmetic number, because the mean of its divisors is an integer number (4960775172).

Almost surely, 29921550343 is an apocalyptic number.

9921550343 is a deficient number, since it is larger than the sum of its proper divisors (1).

9921550343 is an equidigital number, since it uses as much as digits as its factorization.

9921550343 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 145800, while the sum is 41.

The square root of 9921550343 is about 99606.9793889966. The cubic root of 9921550343 is about 2148.7860710234.

The spelling of 9921550343 in words is "nine billion, nine hundred twenty-one million, five hundred fifty thousand, three hundred forty-three".