Search a number
-
+
992212021210499 is a prime number
BaseRepresentation
bin1110000110011010010101110…
…1000100001110110110000011
311211010010112122202002100011122
43201212211131010032312003
52020022400204412213444
613434131524313502455
7415664644563564215
oct34146453504166603
94733115582070148
10992212021210499
11268170834071a11
1293349406411a2b
13337842661325ab
1413703464a985b5
1579a9aa1d6a4ee
hex386695d10ed83

992212021210499 has 2 divisors, whose sum is σ = 992212021210500. Its totient is φ = 992212021210498.

The previous prime is 992212021210433. The next prime is 992212021210513. The reversal of 992212021210499 is 994012120212299.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 992212021210499 - 244 = 974619835166083 is a prime.

It is a super-3 number, since 3×9922120212104993 (a number of 46 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 992212021210499.

It is not a weakly prime, because it can be changed into another prime (992212021212499) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 496106010605249 + 496106010605250.

It is an arithmetic number, because the mean of its divisors is an integer number (496106010605250).

Almost surely, 2992212021210499 is an apocalyptic number.

992212021210499 is a deficient number, since it is larger than the sum of its proper divisors (1).

992212021210499 is an equidigital number, since it uses as much as digits as its factorization.

992212021210499 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 839808, while the sum is 53.

The spelling of 992212021210499 in words is "nine hundred ninety-two trillion, two hundred twelve billion, twenty-one million, two hundred ten thousand, four hundred ninety-nine".