Search a number
-
+
9923644521317 is a prime number
BaseRepresentation
bin1001000001101000011101…
…0011100111101101100101
31022010200122211221001012102
42100122013103213231211
52300042110444140232
633034505342101445
72042650106443262
oct220320723475545
938120584831172
109923644521317
11318665969482a
12114332857a885
1356ca460c12c7
14264442412269
1512320b8cc662
hex906874e7b65

9923644521317 has 2 divisors, whose sum is σ = 9923644521318. Its totient is φ = 9923644521316.

The previous prime is 9923644521313. The next prime is 9923644521361. The reversal of 9923644521317 is 7131254463299.

9923644521317 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9707767201441 + 215877319876 = 3115729^2 + 464626^2 .

It is a cyclic number.

It is not a de Polignac number, because 9923644521317 - 22 = 9923644521313 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (9923644521313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4961822260658 + 4961822260659.

It is an arithmetic number, because the mean of its divisors is an integer number (4961822260659).

Almost surely, 29923644521317 is an apocalyptic number.

It is an amenable number.

9923644521317 is a deficient number, since it is larger than the sum of its proper divisors (1).

9923644521317 is an equidigital number, since it uses as much as digits as its factorization.

9923644521317 is an evil number, because the sum of its binary digits is even.

The product of its digits is 9797760, while the sum is 56.

The spelling of 9923644521317 in words is "nine trillion, nine hundred twenty-three billion, six hundred forty-four million, five hundred twenty-one thousand, three hundred seventeen".