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99238182913 is a prime number
BaseRepresentation
bin101110001101100001…
…1101000000000000001
3100111011002011000200001
41130123003220000001
53111214433323123
6113331150400001
710112133431302
oct1343303500001
9314132130601
1099238182913
11390a5404701
1217296800001
139486a382bc
144b35bd47a9
1528ac4060ad
hex171b0e8001

99238182913 has 2 divisors, whose sum is σ = 99238182914. Its totient is φ = 99238182912.

The previous prime is 99238182889. The next prime is 99238182937. The reversal of 99238182913 is 31928183299.

It is a balanced prime because it is at equal distance from previous prime (99238182889) and next prime (99238182937).

It can be written as a sum of positive squares in only one way, i.e., 95816868849 + 3421314064 = 309543^2 + 58492^2 .

It is an emirp because it is prime and its reverse (31928183299) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 99238182913 - 221 = 99236085761 is a prime.

It is not a weakly prime, because it can be changed into another prime (99238182983) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49619091456 + 49619091457.

It is an arithmetic number, because the mean of its divisors is an integer number (49619091457).

Almost surely, 299238182913 is an apocalyptic number.

It is an amenable number.

99238182913 is a deficient number, since it is larger than the sum of its proper divisors (1).

99238182913 is an equidigital number, since it uses as much as digits as its factorization.

99238182913 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1679616, while the sum is 55.

The spelling of 99238182913 in words is "ninety-nine billion, two hundred thirty-eight million, one hundred eighty-two thousand, nine hundred thirteen".