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9925140593 is a prime number
BaseRepresentation
bin10010011111001010…
…11010000001110001
3221121200220101022202
421033211122001301
5130311313444333
64320510112545
7500645205644
oct111745320161
927550811282
109925140593
114233535035
121b0baab755
13c22339b74
146a2237a5b
153d15225e8
hex24f95a071

9925140593 has 2 divisors, whose sum is σ = 9925140594. Its totient is φ = 9925140592.

The previous prime is 9925140587. The next prime is 9925140601. The reversal of 9925140593 is 3950415299.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9026520064 + 898620529 = 95008^2 + 29977^2 .

It is an emirp because it is prime and its reverse (3950415299) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 9925140593 - 210 = 9925139569 is a prime.

It is not a weakly prime, because it can be changed into another prime (9925140553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4962570296 + 4962570297.

It is an arithmetic number, because the mean of its divisors is an integer number (4962570297).

Almost surely, 29925140593 is an apocalyptic number.

It is an amenable number.

9925140593 is a deficient number, since it is larger than the sum of its proper divisors (1).

9925140593 is an equidigital number, since it uses as much as digits as its factorization.

9925140593 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 437400, while the sum is 47.

The square root of 9925140593 is about 99624.9998393977. Note that the first 3 decimals coincide. The cubic root of 9925140593 is about 2149.0452290702.

The spelling of 9925140593 in words is "nine billion, nine hundred twenty-five million, one hundred forty thousand, five hundred ninety-three".