Base | Representation |
---|---|
bin | 10010011111001010… |
… | …11010000001110001 |
3 | 221121200220101022202 |
4 | 21033211122001301 |
5 | 130311313444333 |
6 | 4320510112545 |
7 | 500645205644 |
oct | 111745320161 |
9 | 27550811282 |
10 | 9925140593 |
11 | 4233535035 |
12 | 1b0baab755 |
13 | c22339b74 |
14 | 6a2237a5b |
15 | 3d15225e8 |
hex | 24f95a071 |
9925140593 has 2 divisors, whose sum is σ = 9925140594. Its totient is φ = 9925140592.
The previous prime is 9925140587. The next prime is 9925140601. The reversal of 9925140593 is 3950415299.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9026520064 + 898620529 = 95008^2 + 29977^2 .
It is an emirp because it is prime and its reverse (3950415299) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 9925140593 - 210 = 9925139569 is a prime.
It is not a weakly prime, because it can be changed into another prime (9925140553) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4962570296 + 4962570297.
It is an arithmetic number, because the mean of its divisors is an integer number (4962570297).
Almost surely, 29925140593 is an apocalyptic number.
It is an amenable number.
9925140593 is a deficient number, since it is larger than the sum of its proper divisors (1).
9925140593 is an equidigital number, since it uses as much as digits as its factorization.
9925140593 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 437400, while the sum is 47.
The square root of 9925140593 is about 99624.9998393977. Note that the first 3 decimals coincide. The cubic root of 9925140593 is about 2149.0452290702.
The spelling of 9925140593 in words is "nine billion, nine hundred twenty-five million, one hundred forty thousand, five hundred ninety-three".
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