Base | Representation |
---|---|
bin | 10010011111001011… |
… | …00110010110001101 |
3 | 221121200222221112122 |
4 | 21033211212112031 |
5 | 130311322103203 |
6 | 4320511142325 |
7 | 500645506031 |
oct | 111745462615 |
9 | 27550887478 |
10 | 9925191053 |
11 | 4233569a38 |
12 | 1b0bb149a5 |
13 | c22356b1b |
14 | 6a224c1c1 |
15 | 3d1532538 |
hex | 24f96658d |
9925191053 has 2 divisors, whose sum is σ = 9925191054. Its totient is φ = 9925191052.
The previous prime is 9925191013. The next prime is 9925191079. The reversal of 9925191053 is 3501915299.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9686890084 + 238300969 = 98422^2 + 15437^2 .
It is a cyclic number.
It is not a de Polignac number, because 9925191053 - 214 = 9925174669 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 9925190995 and 9925191013.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (9925191013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4962595526 + 4962595527.
It is an arithmetic number, because the mean of its divisors is an integer number (4962595527).
Almost surely, 29925191053 is an apocalyptic number.
It is an amenable number.
9925191053 is a deficient number, since it is larger than the sum of its proper divisors (1).
9925191053 is an equidigital number, since it uses as much as digits as its factorization.
9925191053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 109350, while the sum is 44.
The square root of 9925191053 is about 99625.2530887626. The cubic root of 9925191053 is about 2149.0488710216.
The spelling of 9925191053 in words is "nine billion, nine hundred twenty-five million, one hundred ninety-one thousand, fifty-three".
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