Base | Representation |
---|---|
bin | 11100111000110000000… |
… | …00000000000001000111 |
3 | 10111212220211022011121202 |
4 | 32130120000000001013 |
5 | 112230210231124011 |
6 | 2035544442533115 |
7 | 131465032431314 |
oct | 16343000000107 |
9 | 3455824264552 |
10 | 992540098631 |
11 | 352a30012654 |
12 | 14043b80719b |
13 | 7279990a213 |
14 | 360797b1d0b |
15 | 1ac418a523b |
hex | e718000047 |
992540098631 has 2 divisors, whose sum is σ = 992540098632. Its totient is φ = 992540098630.
The previous prime is 992540098547. The next prime is 992540098657. The reversal of 992540098631 is 136890045299.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 992540098631 - 230 = 991466356807 is a prime.
It is a super-3 number, since 3×9925400986313 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (992540098661) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 496270049315 + 496270049316.
It is an arithmetic number, because the mean of its divisors is an integer number (496270049316).
Almost surely, 2992540098631 is an apocalyptic number.
992540098631 is a deficient number, since it is larger than the sum of its proper divisors (1).
992540098631 is an equidigital number, since it uses as much as digits as its factorization.
992540098631 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4199040, while the sum is 56.
The spelling of 992540098631 in words is "nine hundred ninety-two billion, five hundred forty million, ninety-eight thousand, six hundred thirty-one".
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