9928403 has 2 divisors, whose sum is σ = 9928404. Its totient is φ = 9928402.

The previous prime is 9928397. The next prime is 9928409. The reversal of 9928403 is 3048299.

It is a balanced prime because it is at equal distance from previous prime (9928397) and next prime (9928409).

It is a cyclic number.

It is not a de Polignac number, because 9928403 - 2¹⁸ = 9666259 is a prime.

It is a super-3 number, since 3×9928403³ (a number of 22 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (9928409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4964201 + 4964202.

It is an arithmetic number, because the mean of its divisors is an integer number (4964202).

Almost surely, 2^9928403 is an apocalyptic number.

9928403 is a deficient number, since it is larger than the sum of its proper divisors (1).

9928403 is an equidigital number, since it uses as much as digits as its factorization.

9928403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 35.

The square root of 9928403 is about 3150.9368448130. The cubic root of 9928403 is about 214.9280667957.

The spelling of 9928403 in words is "nine million, nine hundred twenty-eight thousand, four hundred three".