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99400505003 is a prime number
BaseRepresentation
bin101110010010010111…
…0110101011010101011
3100111120101120211201022
41130210232311122223
53112033012130003
6113355225443055
710116144231452
oct1344456653253
9314511524638
1099400505003
1139178aa2698
121732104048b
1394b155c987
144b4d5a9b99
1528bb7bb738
hex1724bb56ab

99400505003 has 2 divisors, whose sum is σ = 99400505004. Its totient is φ = 99400505002.

The previous prime is 99400504999. The next prime is 99400505053. The reversal of 99400505003 is 30050500499.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 99400505003 - 22 = 99400504999 is a prime.

It is not a weakly prime, because it can be changed into another prime (99400505053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49700252501 + 49700252502.

It is an arithmetic number, because the mean of its divisors is an integer number (49700252502).

Almost surely, 299400505003 is an apocalyptic number.

99400505003 is a deficient number, since it is larger than the sum of its proper divisors (1).

99400505003 is an equidigital number, since it uses as much as digits as its factorization.

99400505003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24300, while the sum is 35.

The spelling of 99400505003 in words is "ninety-nine billion, four hundred million, five hundred five thousand, three".