Base | Representation |
---|---|
bin | 101110010010010111… |
… | …0110101011011011101 |
3 | 100111120101120211210011 |
4 | 1130210232311123131 |
5 | 3112033012130203 |
6 | 113355225443221 |
7 | 10116144231553 |
oct | 1344456653335 |
9 | 314511524704 |
10 | 99400505053 |
11 | 39178aa2733 |
12 | 17321040511 |
13 | 94b155c9c5 |
14 | 4b4d5a9bd3 |
15 | 28bb7bb76d |
hex | 1724bb56dd |
99400505053 has 2 divisors, whose sum is σ = 99400505054. Its totient is φ = 99400505052.
The previous prime is 99400505003. The next prime is 99400505123. The reversal of 99400505053 is 35050500499.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 53066651044 + 46333854009 = 230362^2 + 215253^2 .
It is a cyclic number.
It is not a de Polignac number, because 99400505053 - 213 = 99400496861 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 99400504997 and 99400505015.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (99400505003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49700252526 + 49700252527.
It is an arithmetic number, because the mean of its divisors is an integer number (49700252527).
Almost surely, 299400505053 is an apocalyptic number.
It is an amenable number.
99400505053 is a deficient number, since it is larger than the sum of its proper divisors (1).
99400505053 is an equidigital number, since it uses as much as digits as its factorization.
99400505053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 121500, while the sum is 40.
The spelling of 99400505053 in words is "ninety-nine billion, four hundred million, five hundred five thousand, fifty-three".
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