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99414362381 is a prime number
BaseRepresentation
bin101110010010110001…
…1101100100100001101
3100111121100122212110112
41130211203230210031
53112100034044011
6113400442445405
710116403065125
oct1344543544415
9314540585415
1099414362381
11391858a7974
1217325803865
1394b43a21c9
144b51375c85
1528bcb0758b
hex17258ec90d

99414362381 has 2 divisors, whose sum is σ = 99414362382. Its totient is φ = 99414362380.

The previous prime is 99414362329. The next prime is 99414362419. The reversal of 99414362381 is 18326341499.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 65717886025 + 33696476356 = 256355^2 + 183566^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-99414362381 is a prime.

It is a super-2 number, since 2×994143623812 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (99414362581) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49707181190 + 49707181191.

It is an arithmetic number, because the mean of its divisors is an integer number (49707181191).

Almost surely, 299414362381 is an apocalyptic number.

It is an amenable number.

99414362381 is a deficient number, since it is larger than the sum of its proper divisors (1).

99414362381 is an equidigital number, since it uses as much as digits as its factorization.

99414362381 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1119744, while the sum is 50.

The spelling of 99414362381 in words is "ninety-nine billion, four hundred fourteen million, three hundred sixty-two thousand, three hundred eighty-one".