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9947668697 is a prime number
BaseRepresentation
bin10010100001110110…
…10110000011011001
3221200021021221001222
421100323112003121
5130333100344242
64323033021425
7501340534361
oct112073260331
927607257058
109947668697
1142452217aa
121b17554875
13c26bc6bc5
146a521d9a1
153d34c25d2
hex250ed60d9

9947668697 has 2 divisors, whose sum is σ = 9947668698. Its totient is φ = 9947668696.

The previous prime is 9947668693. The next prime is 9947668699. The reversal of 9947668697 is 7968667499.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5358825616 + 4588843081 = 73204^2 + 67741^2 .

It is a cyclic number.

It is not a de Polignac number, because 9947668697 - 22 = 9947668693 is a prime.

It is a super-2 number, since 2×99476686972 (a number of 21 digits) contains 22 as substring.

Together with 9947668699, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 9947668697.

It is not a weakly prime, because it can be changed into another prime (9947668693) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4973834348 + 4973834349.

It is an arithmetic number, because the mean of its divisors is an integer number (4973834349).

Almost surely, 29947668697 is an apocalyptic number.

It is an amenable number.

9947668697 is a deficient number, since it is larger than the sum of its proper divisors (1).

9947668697 is an equidigital number, since it uses as much as digits as its factorization.

9947668697 is an evil number, because the sum of its binary digits is even.

The product of its digits is 246903552, while the sum is 71.

The square root of 9947668697 is about 99738.0002656961. Note that the first 3 decimals coincide. The cubic root of 9947668697 is about 2150.6699694652.

The spelling of 9947668697 in words is "nine billion, nine hundred forty-seven million, six hundred sixty-eight thousand, six hundred ninety-seven".