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99478763 is a prime number
BaseRepresentation
bin1011110110111…
…10110011101011
320221012001012122
411323132303223
5200431310023
613512101455
72315361356
oct573366353
9227161178
1099478763
115117595a
122939488b
13177c0497
14d2d729d
158b002c8
hex5edeceb

99478763 has 2 divisors, whose sum is σ = 99478764. Its totient is φ = 99478762.

The previous prime is 99478723. The next prime is 99478793. The reversal of 99478763 is 36787499.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 99478763 - 214 = 99462379 is a prime.

It is a super-3 number, since 3×994787633 (a number of 25 digits) contains 333 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (99478723) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49739381 + 49739382.

It is an arithmetic number, because the mean of its divisors is an integer number (49739382).

Almost surely, 299478763 is an apocalyptic number.

99478763 is a deficient number, since it is larger than the sum of its proper divisors (1).

99478763 is an equidigital number, since it uses as much as digits as its factorization.

99478763 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2286144, while the sum is 53.

The square root of 99478763 is about 9973.9041002007. The cubic root of 99478763 is about 463.3510221611.

The spelling of 99478763 in words is "ninety-nine million, four hundred seventy-eight thousand, seven hundred sixty-three".