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9951493265353 is a prime number
BaseRepresentation
bin1001000011010000001100…
…1110001001011111001001
31022020100112200020211011201
42100310003032021133021
52301021124233442403
633055353005224201
72044654165036663
oct220640316113711
938210480224151
109951493265353
11319744a571372
1211487bab62061
13572563890583
14265924c6b533
15123cdb71721d
hex90d033897c9

9951493265353 has 2 divisors, whose sum is σ = 9951493265354. Its totient is φ = 9951493265352.

The previous prime is 9951493265333. The next prime is 9951493265383. The reversal of 9951493265353 is 3535623941599.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8957378580544 + 994114684809 = 2992888^2 + 997053^2 .

It is a cyclic number.

It is not a de Polignac number, because 9951493265353 - 25 = 9951493265321 is a prime.

It is a super-2 number, since 2×99514932653532 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (9951493265333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4975746632676 + 4975746632677.

It is an arithmetic number, because the mean of its divisors is an integer number (4975746632677).

Almost surely, 29951493265353 is an apocalyptic number.

It is an amenable number.

9951493265353 is a deficient number, since it is larger than the sum of its proper divisors (1).

9951493265353 is an equidigital number, since it uses as much as digits as its factorization.

9951493265353 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 118098000, while the sum is 64.

The spelling of 9951493265353 in words is "nine trillion, nine hundred fifty-one billion, four hundred ninety-three million, two hundred sixty-five thousand, three hundred fifty-three".