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9952807115033 is a prime number
BaseRepresentation
bin1001000011010101000110…
…0010000101100100011001
31022020110221020111022002222
42100311101202011210121
52301031322110140113
633100131221433425
72045031560422346
oct220652142054431
938213836438088
109952807115033
113197a64169052
121148b06b6b875
13572712b37413
14265a0b5557cd
15123d66c40e08
hex90d51885919

9952807115033 has 2 divisors, whose sum is σ = 9952807115034. Its totient is φ = 9952807115032.

The previous prime is 9952807115021. The next prime is 9952807115077. The reversal of 9952807115033 is 3305117082599.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9631259144329 + 321547970704 = 3103427^2 + 567052^2 .

It is an emirp because it is prime and its reverse (3305117082599) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 9952807115033 - 212 = 9952807110937 is a prime.

It is a super-3 number, since 3×99528071150333 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (9952807115533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4976403557516 + 4976403557517.

It is an arithmetic number, because the mean of its divisors is an integer number (4976403557517).

Almost surely, 29952807115033 is an apocalyptic number.

It is an amenable number.

9952807115033 is a deficient number, since it is larger than the sum of its proper divisors (1).

9952807115033 is an equidigital number, since it uses as much as digits as its factorization.

9952807115033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2041200, while the sum is 53.

The spelling of 9952807115033 in words is "nine trillion, nine hundred fifty-two billion, eight hundred seven million, one hundred fifteen thousand, thirty-three".