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99561343313 is a prime number
BaseRepresentation
bin101110010111001010…
…0011000100101010001
3100111222121020021101202
41130232110120211101
53112400200441223
6113423213040545
710123136312015
oct1345624304521
9314877207352
1099561343313
1139250867913
1217366a86155
139508984b83
144b66ab6545
1528ca98c428
hex172e518951

99561343313 has 2 divisors, whose sum is σ = 99561343314. Its totient is φ = 99561343312.

The previous prime is 99561343307. The next prime is 99561343411. The reversal of 99561343313 is 31334316599.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 96765789184 + 2795554129 = 311072^2 + 52873^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-99561343313 is a prime.

It is a super-2 number, since 2×995613433132 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (99561343303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49780671656 + 49780671657.

It is an arithmetic number, because the mean of its divisors is an integer number (49780671657).

Almost surely, 299561343313 is an apocalyptic number.

It is an amenable number.

99561343313 is a deficient number, since it is larger than the sum of its proper divisors (1).

99561343313 is an equidigital number, since it uses as much as digits as its factorization.

99561343313 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 787320, while the sum is 47.

The spelling of 99561343313 in words is "ninety-nine billion, five hundred sixty-one million, three hundred forty-three thousand, three hundred thirteen".