Base | Representation |
---|---|
bin | 10010100011011101… |
… | …01101101100110101 |
3 | 221201012122002020021 |
4 | 21101232231230311 |
5 | 130400022304101 |
6 | 4324233405141 |
7 | 501563151424 |
oct | 112156555465 |
9 | 27635562207 |
10 | 9961134901 |
11 | 425188a0a3 |
12 | 1b1bb697b1 |
13 | c29930383 |
14 | 6a6d272bb |
15 | 3d47825a1 |
hex | 251badb35 |
9961134901 has 2 divisors, whose sum is σ = 9961134902. Its totient is φ = 9961134900.
The previous prime is 9961134889. The next prime is 9961134907. The reversal of 9961134901 is 1094311699.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9700280100 + 260854801 = 98490^2 + 16151^2 .
It is a cyclic number.
It is not a de Polignac number, because 9961134901 - 215 = 9961102133 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (9961134907) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4980567450 + 4980567451.
It is an arithmetic number, because the mean of its divisors is an integer number (4980567451).
Almost surely, 29961134901 is an apocalyptic number.
It is an amenable number.
9961134901 is a deficient number, since it is larger than the sum of its proper divisors (1).
9961134901 is an equidigital number, since it uses as much as digits as its factorization.
9961134901 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 52488, while the sum is 43.
The square root of 9961134901 is about 99805.4853252064. The cubic root of 9961134901 is about 2151.6399891040.
The spelling of 9961134901 in words is "nine billion, nine hundred sixty-one million, one hundred thirty-four thousand, nine hundred one".
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