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996449069333 is a prime number
BaseRepresentation
bin11101000000000001111…
…11100010100100010101
310112021000020201110100102
432200000333202210111
5112311211430204313
62041432401423445
7131663636224334
oct16400077424425
93467006643312
10996449069333
11354656582153
1214115093ab85
1372c70709333
143632a9cbd1b
151adbeb48a58
hexe800fe2915

996449069333 has 2 divisors, whose sum is σ = 996449069334. Its totient is φ = 996449069332.

The previous prime is 996449069303. The next prime is 996449069339. The reversal of 996449069333 is 333960944699.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 817031594404 + 179417474929 = 903898^2 + 423577^2 .

It is a cyclic number.

It is not a de Polignac number, because 996449069333 - 212 = 996449065237 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 996449069333.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (996449069339) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 498224534666 + 498224534667.

It is an arithmetic number, because the mean of its divisors is an integer number (498224534667).

Almost surely, 2996449069333 is an apocalyptic number.

It is an amenable number.

996449069333 is a deficient number, since it is larger than the sum of its proper divisors (1).

996449069333 is an equidigital number, since it uses as much as digits as its factorization.

996449069333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 102036672, while the sum is 65.

The spelling of 996449069333 in words is "nine hundred ninety-six billion, four hundred forty-nine million, sixty-nine thousand, three hundred thirty-three".