Base | Representation |
---|---|
bin | 10010100100100010… |
… | …01000000001001001 |
3 | 221201211121101021222 |
4 | 21102101020001021 |
5 | 130404324434333 |
6 | 4325155011425 |
7 | 502032632006 |
oct | 112221100111 |
9 | 27654541258 |
10 | 9970155593 |
11 | 4256990512 |
12 | 1b22b99b75 |
13 | c2b76b268 |
14 | 6a81d48ad |
15 | 3d5465298 |
hex | 252448049 |
9970155593 has 2 divisors, whose sum is σ = 9970155594. Its totient is φ = 9970155592.
The previous prime is 9970155583. The next prime is 9970155599. The reversal of 9970155593 is 3955510799.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9933710224 + 36445369 = 99668^2 + 6037^2 .
It is an emirp because it is prime and its reverse (3955510799) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 9970155593 - 218 = 9969893449 is a prime.
It is a zygodrome in base 8.
It is not a weakly prime, because it can be changed into another prime (9970155599) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4985077796 + 4985077797.
It is an arithmetic number, because the mean of its divisors is an integer number (4985077797).
Almost surely, 29970155593 is an apocalyptic number.
It is an amenable number.
9970155593 is a deficient number, since it is larger than the sum of its proper divisors (1).
9970155593 is an equidigital number, since it uses as much as digits as its factorization.
9970155593 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1913625, while the sum is 53.
The square root of 9970155593 is about 99850.6664624728. Note that the first 3 decimals coincide. The cubic root of 9970155593 is about 2152.2892934866.
The spelling of 9970155593 in words is "nine billion, nine hundred seventy million, one hundred fifty-five thousand, five hundred ninety-three".
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