Search a number
-
+
997345651 is a prime number
BaseRepresentation
bin111011011100100…
…100100101110011
32120111200102000211
4323130210211303
54020310030101
6242544324551
733500204161
oct7334444563
92514612024
10997345651
11471a80605
1223a013757
1312b81ac73
149665a231
155c859c51
hex3b724973

997345651 has 2 divisors, whose sum is σ = 997345652. Its totient is φ = 997345650.

The previous prime is 997345649. The next prime is 997345667. The reversal of 997345651 is 156543799.

It is a weak prime.

It is an emirp because it is prime and its reverse (156543799) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 997345651 - 21 = 997345649 is a prime.

It is a super-3 number, since 3×9973456513 (a number of 28 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 997345649, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 997345595 and 997345604.

It is not a weakly prime, because it can be changed into another prime (997343651) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 498672825 + 498672826.

It is an arithmetic number, because the mean of its divisors is an integer number (498672826).

Almost surely, 2997345651 is an apocalyptic number.

997345651 is a deficient number, since it is larger than the sum of its proper divisors (1).

997345651 is an equidigital number, since it uses as much as digits as its factorization.

997345651 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1020600, while the sum is 49.

The square root of 997345651 is about 31580.7797718802. The cubic root of 997345651 is about 999.1144330026.

The spelling of 997345651 in words is "nine hundred ninety-seven million, three hundred forty-five thousand, six hundred fifty-one".