Base | Representation |
---|---|
bin | 11101000010000100011… |
… | …10100000000110100001 |
3 | 10112100211112002211021222 |
4 | 32201002032200012201 |
5 | 112320432114313213 |
6 | 2042133135224425 |
7 | 132033025635611 |
oct | 16410216400641 |
9 | 3470745084258 |
10 | 997543510433 |
11 | 35506833aa28 |
12 | 1413b7378115 |
13 | 730b6391a12 |
14 | 363d20c0a41 |
15 | 1ae35c82808 |
hex | e8423a01a1 |
997543510433 has 2 divisors, whose sum is σ = 997543510434. Its totient is φ = 997543510432.
The previous prime is 997543510421. The next prime is 997543510463. The reversal of 997543510433 is 334015345799.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 523955927104 + 473587583329 = 723848^2 + 688177^2 .
It is a cyclic number.
It is not a de Polignac number, because 997543510433 - 210 = 997543509409 is a prime.
It is not a weakly prime, because it can be changed into another prime (997543510463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 498771755216 + 498771755217.
It is an arithmetic number, because the mean of its divisors is an integer number (498771755217).
Almost surely, 2997543510433 is an apocalyptic number.
It is an amenable number.
997543510433 is a deficient number, since it is larger than the sum of its proper divisors (1).
997543510433 is an equidigital number, since it uses as much as digits as its factorization.
997543510433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6123600, while the sum is 53.
The spelling of 997543510433 in words is "nine hundred ninety-seven billion, five hundred forty-three million, five hundred ten thousand, four hundred thirty-three".
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