Search a number
-
+
9977765432113 is a prime number
BaseRepresentation
bin1001000100110010000100…
…1010100000101100110001
31022022212100121222011201001
42101030201022200230301
52301433430422311423
633115415553042001
72046604220546233
oct221144112405461
938285317864631
109977765432113
1131a7601515086
121151911556301
13574b8c83808b
14266cd816c253
15124827e2ccad
hex913212a0b31

9977765432113 has 2 divisors, whose sum is σ = 9977765432114. Its totient is φ = 9977765432112.

The previous prime is 9977765432099. The next prime is 9977765432191. The reversal of 9977765432113 is 3112345677799.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7524306844209 + 2453458587904 = 2743047^2 + 1566352^2 .

It is a cyclic number.

It is not a de Polignac number, because 9977765432113 - 217 = 9977765301041 is a prime.

It is a super-3 number, since 3×99777654321133 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (9977765432513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4988882716056 + 4988882716057.

It is an arithmetic number, because the mean of its divisors is an integer number (4988882716057).

Almost surely, 29977765432113 is an apocalyptic number.

It is an amenable number.

9977765432113 is a deficient number, since it is larger than the sum of its proper divisors (1).

9977765432113 is an equidigital number, since it uses as much as digits as its factorization.

9977765432113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 60011280, while the sum is 64.

The spelling of 9977765432113 in words is "nine trillion, nine hundred seventy-seven billion, seven hundred sixty-five million, four hundred thirty-two thousand, one hundred thirteen".