Base | Representation |
---|---|
bin | 111011100000101… |
… | …001001010101011 |
3 | 2120120200122010012 |
4 | 323200221022223 |
5 | 4021043203341 |
6 | 243023242135 |
7 | 33512240663 |
oct | 7340511253 |
9 | 2516618105 |
10 | 998412971 |
11 | 47263a496 |
12 | 23a44934b |
13 | 12bb02a0a |
14 | 968571a3 |
15 | 5c9bb0eb |
hex | 3b8292ab |
998412971 has 2 divisors, whose sum is σ = 998412972. Its totient is φ = 998412970.
The previous prime is 998412923. The next prime is 998412973. The reversal of 998412971 is 179214899.
998412971 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-998412971 is a prime.
It is a super-2 number, since 2×9984129712 = 1993656921322093682, which contains 22 as substring.
Together with 998412973, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (998412973) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 499206485 + 499206486.
It is an arithmetic number, because the mean of its divisors is an integer number (499206486).
Almost surely, 2998412971 is an apocalyptic number.
998412971 is a deficient number, since it is larger than the sum of its proper divisors (1).
998412971 is an equidigital number, since it uses as much as digits as its factorization.
998412971 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 326592, while the sum is 50.
The square root of 998412971 is about 31597.6735061302. The cubic root of 998412971 is about 999.4707102351.
The spelling of 998412971 in words is "nine hundred ninety-eight million, four hundred twelve thousand, nine hundred seventy-one".
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