998426000953 has 2 divisors, whose sum is σ = 998426000954. Its totient is φ = 998426000952.

The previous prime is 998426000917. The next prime is 998426000969. The reversal of 998426000953 is 359000624899.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 503834494969 + 494591505984 = 709813^2 + 703272^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-998426000953 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 998426000894 and 998426000903.

It is not a weakly prime, because it can be changed into another prime (998426000903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 499213000476 + 499213000477.

It is an arithmetic number, because the mean of its divisors is an integer number (499213000477).

Almost surely, 2^998426000953 is an apocalyptic number.

It is an amenable number.

998426000953 is a deficient number, since it is larger than the sum of its proper divisors (1).

998426000953 is an equidigital number, since it uses as much as digits as its factorization.

998426000953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4199040, while the sum is 55.

The spelling of 998426000953 in words is "nine hundred ninety-eight billion, four hundred twenty-six million, nine hundred fifty-three", and thus it is an aban number.