Base | Representation |
---|---|
bin | 1001000101100100101100… |
… | …1011001011011100010111 |
3 | 1022101011102201102110222102 |
4 | 2101121023023023130113 |
5 | 2302144243404332101 |
6 | 33125544251552315 |
7 | 2050565044346252 |
oct | 221311313133427 |
9 | 38334381373872 |
10 | 9991355152151 |
11 | 320234556696a |
12 | 115448475b69b |
13 | 576247146539 |
14 | 267826d66099 |
15 | 124d7101b86b |
hex | 9164b2cb717 |
9991355152151 has 2 divisors, whose sum is σ = 9991355152152. Its totient is φ = 9991355152150.
The previous prime is 9991355152061. The next prime is 9991355152231. The reversal of 9991355152151 is 1512515531999.
9991355152151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 9991355152151 - 218 = 9991354890007 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (9991355152651) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4995677576075 + 4995677576076.
It is an arithmetic number, because the mean of its divisors is an integer number (4995677576076).
Almost surely, 29991355152151 is an apocalyptic number.
9991355152151 is a deficient number, since it is larger than the sum of its proper divisors (1).
9991355152151 is an equidigital number, since it uses as much as digits as its factorization.
9991355152151 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2733750, while the sum is 56.
The spelling of 9991355152151 in words is "nine trillion, nine hundred ninety-one billion, three hundred fifty-five million, one hundred fifty-two thousand, one hundred fifty-one".
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