Base | Representation |
---|---|
bin | 101110100001110001… |
… | …0111001001100110111 |
3 | 100112220102100022021102 |
4 | 1131003202321030313 |
5 | 3114112332442341 |
6 | 113522414040315 |
7 | 10135022316542 |
oct | 1350342711467 |
9 | 315812308242 |
10 | 99917468471 |
11 | 39413895a27 |
12 | 174461a909b |
13 | 95646a4012 |
14 | 4b9c0d9859 |
15 | 28ebd85c9b |
hex | 17438b9337 |
99917468471 has 2 divisors, whose sum is σ = 99917468472. Its totient is φ = 99917468470.
The previous prime is 99917468461. The next prime is 99917468587. The reversal of 99917468471 is 17486471999.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-99917468471 is a prime.
It is a super-3 number, since 3×999174684713 (a number of 34 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 99917468398 and 99917468407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (99917468461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49958734235 + 49958734236.
It is an arithmetic number, because the mean of its divisors is an integer number (49958734236).
Almost surely, 299917468471 is an apocalyptic number.
99917468471 is a deficient number, since it is larger than the sum of its proper divisors (1).
99917468471 is an equidigital number, since it uses as much as digits as its factorization.
99917468471 is an evil number, because the sum of its binary digits is even.
The product of its digits is 27433728, while the sum is 65.
The spelling of 99917468471 in words is "ninety-nine billion, nine hundred seventeen million, four hundred sixty-eight thousand, four hundred seventy-one".
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