Base | Representation |
---|---|
bin | 101110100010000001… |
… | …1100111110010000001 |
3 | 100112221000111012000001 |
4 | 1131010003213302001 |
5 | 3114122032012443 |
6 | 113523322000001 |
7 | 10135155251431 |
oct | 1350403476201 |
9 | 315830435001 |
10 | 99926047873 |
11 | 39418715843 |
12 | 17449046001 |
13 | 95663b90a2 |
14 | 4b9d2d02c1 |
15 | 28ec9ccd4d |
hex | 17440e7c81 |
99926047873 has 2 divisors, whose sum is σ = 99926047874. Its totient is φ = 99926047872.
The previous prime is 99926047831. The next prime is 99926047927. The reversal of 99926047873 is 37874062999.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 99308177424 + 617870449 = 315132^2 + 24857^2 .
It is an emirp because it is prime and its reverse (37874062999) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-99926047873 is a prime.
It is not a weakly prime, because it can be changed into another prime (99926047813) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49963023936 + 49963023937.
It is an arithmetic number, because the mean of its divisors is an integer number (49963023937).
Almost surely, 299926047873 is an apocalyptic number.
It is an amenable number.
99926047873 is a deficient number, since it is larger than the sum of its proper divisors (1).
99926047873 is an equidigital number, since it uses as much as digits as its factorization.
99926047873 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41150592, while the sum is 64.
The spelling of 99926047873 in words is "ninety-nine billion, nine hundred twenty-six million, forty-seven thousand, eight hundred seventy-three".
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