9994050113 has 2 divisors, whose sum is σ = 9994050114. Its totient is φ = 9994050112.

The previous prime is 9994050089. The next prime is 9994050119. The reversal of 9994050113 is 3110504999.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7010377984 + 2983672129 = 83728^2 + 54623^2 .

It is a cyclic number.

It is not a de Polignac number, because 9994050113 - 2¹⁰ = 9994049089 is a prime.

It is a super-2 number, since 2×9994050113² (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (9994050119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4997025056 + 4997025057.

It is an arithmetic number, because the mean of its divisors is an integer number (4997025057).

Almost surely, 2^9994050113 is an apocalyptic number.

It is an amenable number.

9994050113 is a deficient number, since it is larger than the sum of its proper divisors (1).

9994050113 is an equidigital number, since it uses as much as digits as its factorization.

9994050113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 43740, while the sum is 41.

The square root of 9994050113 is about 99970.2461385386. The cubic root of 9994050113 is about 2154.0073171615.

The spelling of 9994050113 in words is "nine billion, nine hundred ninety-four million, fifty thousand, one hundred thirteen".