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999819313153 is a prime number
BaseRepresentation
bin11101000110010011110…
…00000000000000000001
310112120201010102120201121
432203021320000000001
5112340112221010103
62043151033432241
7132143311640143
oct16431170000001
93476633376647
10999819313153
11356025a34221
1214193156b681
1373389a1414b
143656a450c93
151b01a9746bd
hexe8c9e00001

999819313153 has 2 divisors, whose sum is σ = 999819313154. Its totient is φ = 999819313152.

The previous prime is 999819313151. The next prime is 999819313193. The reversal of 999819313153 is 351313918999.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 530824444929 + 468994868224 = 728577^2 + 684832^2 .

It is a cyclic number.

It is not a de Polignac number, because 999819313153 - 21 = 999819313151 is a prime.

Together with 999819313151, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 999819313091 and 999819313100.

It is not a weakly prime, because it can be changed into another prime (999819313151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 499909656576 + 499909656577.

It is an arithmetic number, because the mean of its divisors is an integer number (499909656577).

It is a Proth number, since it is equal to 476751 ⋅ 221 + 1 and 476751 < 221.

Almost surely, 2999819313153 is an apocalyptic number.

It is an amenable number.

999819313153 is a deficient number, since it is larger than the sum of its proper divisors (1).

999819313153 is an equidigital number, since it uses as much as digits as its factorization.

999819313153 is an evil number, because the sum of its binary digits is even.

The product of its digits is 7085880, while the sum is 61.

The spelling of 999819313153 in words is "nine hundred ninety-nine billion, eight hundred nineteen million, three hundred thirteen thousand, one hundred fifty-three".