Base | Representation |
---|---|
bin | 101110100100001101… |
… | …1011101000111010111 |
3 | 100120010010112002101021 |
4 | 1131020123131013113 |
5 | 3114244321421003 |
6 | 113534502142011 |
7 | 10140035625235 |
oct | 1351033350727 |
9 | 316103462337 |
10 | 99999404503 |
11 | 39456069759 |
12 | 17469721907 |
13 | 957866168b |
14 | 4ba8d47955 |
15 | 290416d2bd |
hex | 17486dd1d7 |
99999404503 has 2 divisors, whose sum is σ = 99999404504. Its totient is φ = 99999404502.
The previous prime is 99999404467. The next prime is 99999404509. The reversal of 99999404503 is 30540499999.
It is a strong prime.
It is an emirp because it is prime and its reverse (30540499999) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 99999404503 - 29 = 99999403991 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (99999404509) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49999702251 + 49999702252.
It is an arithmetic number, because the mean of its divisors is an integer number (49999702252).
Almost surely, 299999404503 is an apocalyptic number.
99999404503 is a deficient number, since it is larger than the sum of its proper divisors (1).
99999404503 is an equidigital number, since it uses as much as digits as its factorization.
99999404503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14171760, while the sum is 61.
The spelling of 99999404503 in words is "ninety-nine billion, nine hundred ninety-nine million, four hundred four thousand, five hundred three".
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