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99999404503 is a prime number
BaseRepresentation
bin101110100100001101…
…1011101000111010111
3100120010010112002101021
41131020123131013113
53114244321421003
6113534502142011
710140035625235
oct1351033350727
9316103462337
1099999404503
1139456069759
1217469721907
13957866168b
144ba8d47955
15290416d2bd
hex17486dd1d7

99999404503 has 2 divisors, whose sum is σ = 99999404504. Its totient is φ = 99999404502.

The previous prime is 99999404467. The next prime is 99999404509. The reversal of 99999404503 is 30540499999.

It is a strong prime.

It is an emirp because it is prime and its reverse (30540499999) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 99999404503 - 29 = 99999403991 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (99999404509) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49999702251 + 49999702252.

It is an arithmetic number, because the mean of its divisors is an integer number (49999702252).

Almost surely, 299999404503 is an apocalyptic number.

99999404503 is a deficient number, since it is larger than the sum of its proper divisors (1).

99999404503 is an equidigital number, since it uses as much as digits as its factorization.

99999404503 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14171760, while the sum is 61.

The spelling of 99999404503 in words is "ninety-nine billion, nine hundred ninety-nine million, four hundred four thousand, five hundred three".