10000111122011 has 2 divisors, whose sum is σ = 10000111122012. Its totient is φ = 10000111122010.

The previous prime is 10000111121993. The next prime is 10000111122013. The reversal of 10000111122011 is 11022111100001.

It is a strong prime.

It is an emirp because it is prime and its reverse (11022111100001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10000111122011 is a prime.

Together with 10000111122013, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10000111121983 and 10000111122001.

It is not a weakly prime, because it can be changed into another prime (10000111122013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000055561005 + 5000055561006.

It is an arithmetic number, because the mean of its divisors is an integer number (5000055561006).

Almost surely, 2^{10000111122011} is an apocalyptic number.

10000111122011 is a deficient number, since it is larger than the sum of its proper divisors (1).

10000111122011 is an equidigital number, since it uses as much as digits as its factorization.

10000111122011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4, while the sum is 11.

Adding to 10000111122011 its reverse (11022111100001), we get a palindrome (21022222222012).

The spelling of 10000111122011 in words is "ten trillion, one hundred eleven million, one hundred twenty-two thousand, eleven".