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1000043413001 is a prime number
BaseRepresentation
bin11101000110101110011…
…10110111111000001001
310112121021202010000220222
432203113032313320021
5112341042103204001
62043225200555425
7132152002520363
oct16432716677011
93477252100828
101000043413001
11356130487806
12141994622b75
13733c42889c9
143658c107d33
151b03048e61b
hexe8d73b7e09

1000043413001 has 2 divisors, whose sum is σ = 1000043413002. Its totient is φ = 1000043413000.

The previous prime is 1000043412983. The next prime is 1000043413007. The reversal of 1000043413001 is 1003143400001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 709888817401 + 290154595600 = 842549^2 + 538660^2 .

It is a cyclic number.

It is not a de Polignac number, because 1000043413001 - 26 = 1000043412937 is a prime.

It is not a weakly prime, because it can be changed into another prime (1000043413007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500021706500 + 500021706501.

It is an arithmetic number, because the mean of its divisors is an integer number (500021706501).

Almost surely, 21000043413001 is an apocalyptic number.

It is an amenable number.

1000043413001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1000043413001 is an equidigital number, since it uses as much as digits as its factorization.

1000043413001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 1000043413001 its reverse (1003143400001), we get a palindrome (2003186813002).

The spelling of 1000043413001 in words is "one trillion, forty-three million, four hundred thirteen thousand, one".