Base | Representation |
---|---|
bin | 11101000110101110011… |
… | …10110111111000001111 |
3 | 10112121021202010000221012 |
4 | 32203113032313320033 |
5 | 112341042103204012 |
6 | 2043225200555435 |
7 | 132152002520402 |
oct | 16432716677017 |
9 | 3477252100835 |
10 | 1000043413007 |
11 | 356130487811 |
12 | 141994622b7b |
13 | 733c4288a02 |
14 | 3658c107d39 |
15 | 1b03048e622 |
hex | e8d73b7e0f |
1000043413007 has 2 divisors, whose sum is σ = 1000043413008. Its totient is φ = 1000043413006.
The previous prime is 1000043413001. The next prime is 1000043413081. The reversal of 1000043413007 is 7003143400001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1000043413007 - 236 = 931323936271 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1000043413001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500021706503 + 500021706504.
It is an arithmetic number, because the mean of its divisors is an integer number (500021706504).
Almost surely, 21000043413007 is an apocalyptic number.
1000043413007 is a deficient number, since it is larger than the sum of its proper divisors (1).
1000043413007 is an equidigital number, since it uses as much as digits as its factorization.
1000043413007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 23.
Adding to 1000043413007 its reverse (7003143400001), we get a palindrome (8003186813008).
The spelling of 1000043413007 in words is "one trillion, forty-three million, four hundred thirteen thousand, seven".
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