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100010000112131 is a prime number
BaseRepresentation
bin10110101111010101100100…
…100001111101101000000011
3111010002212021212021212020002
4112233111210201331220003
5101102030440012042011
6552411543151510215
730031325014532144
oct2657254441755003
9433085255255202
10100010000112131
112995900389845a
12b27273682836b
1343a5b96b72465
141a9a71cda3acb
15b867526a0c3b
hex5af56487da03

100010000112131 has 2 divisors, whose sum is σ = 100010000112132. Its totient is φ = 100010000112130.

The previous prime is 100010000112103. The next prime is 100010000112133. The reversal of 100010000112131 is 131211000010001.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 100010000112131 - 246 = 29641255934467 is a prime.

It is a super-2 number, since 2×1000100001121312 (a number of 29 digits) contains 22 as substring.

Together with 100010000112133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (100010000112133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50005000056065 + 50005000056066.

It is an arithmetic number, because the mean of its divisors is an integer number (50005000056066).

Almost surely, 2100010000112131 is an apocalyptic number.

100010000112131 is a deficient number, since it is larger than the sum of its proper divisors (1).

100010000112131 is an equidigital number, since it uses as much as digits as its factorization.

100010000112131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 100010000112131 its reverse (131211000010001), we get a palindrome (231221000122132).

The spelling of 100010000112131 in words is "one hundred trillion, ten billion, one hundred twelve thousand, one hundred thirty-one".