100010130113 has 4 divisors (see below), whose sum is σ = 100425110148. Its totient is φ = 99595150080.

The previous prime is 100010130107. The next prime is 100010130139. The reversal of 100010130113 is 311031010001.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 39135917584 + 60874212529 = 197828^2 + 246727^2 .

It is a cyclic number.

It is not a de Polignac number, because 100010130113 - 2¹⁴ = 100010113729 is a prime.

It is a super-2 number, since 2×100010130113² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100010130094 and 100010130103.

It is not an unprimeable number, because it can be changed into a prime (100010130163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 207489656 + ... + 207490137.

It is an arithmetic number, because the mean of its divisors is an integer number (25106277537).

Almost surely, 2^100010130113 is an apocalyptic number.

It is an amenable number.

100010130113 is a deficient number, since it is larger than the sum of its proper divisors (414980035).

100010130113 is an equidigital number, since it uses as much as digits as its factorization.

100010130113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 414980034.

The product of its (nonzero) digits is 9, while the sum is 11.

Adding to 100010130113 its reverse (311031010001), we get a palindrome (411041140114).

The spelling of 100010130113 in words is "one hundred billion, ten million, one hundred thirty thousand, one hundred thirteen".