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100011221212013 is a prime number
BaseRepresentation
bin10110101111010110101101…
…010100000101101101101101
3111010002222102222000011100122
4112233112231110011231231
5101102040440112241023
6552412304252134325
730031400202650126
oct2657265524055555
9433088388004318
10100011221212013
11299595800a5911
12b272a177673a5
1343a602cb43877
141a9a7d722704d
15b867c49a82c8
hex5af5ad505b6d

100011221212013 has 2 divisors, whose sum is σ = 100011221212014. Its totient is φ = 100011221212012.

The previous prime is 100011221212009. The next prime is 100011221212037. The reversal of 100011221212013 is 310212122110001.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 76100813122084 + 23910408089929 = 8723578^2 + 4889827^2 .

It is a cyclic number.

It is not a de Polignac number, because 100011221212013 - 22 = 100011221212009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100011221211982 and 100011221212000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100011221212213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50005610606006 + 50005610606007.

It is an arithmetic number, because the mean of its divisors is an integer number (50005610606007).

Almost surely, 2100011221212013 is an apocalyptic number.

It is an amenable number.

100011221212013 is a deficient number, since it is larger than the sum of its proper divisors (1).

100011221212013 is an equidigital number, since it uses as much as digits as its factorization.

100011221212013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 100011221212013 its reverse (310212122110001), we get a palindrome (410223343322014).

The spelling of 100011221212013 in words is "one hundred trillion, eleven billion, two hundred twenty-one million, two hundred twelve thousand, thirteen".