100011233513533 has 4 divisors (see below), whose sum is σ = 100116177096348. Its totient is φ = 99906289930720.

The previous prime is 100011233513531. The next prime is 100011233513561. The reversal of 100011233513533 is 335315332110001.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 12304955496964 + 87706278016569 = 3507842^2 + 9365163^2 .

It is a cyclic number.

It is not a de Polignac number, because 100011233513533 - 2¹ = 100011233513531 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100011233513495 and 100011233513504.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100011233513531) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52471789978 + ... + 52471791883.

It is an arithmetic number, because the mean of its divisors is an integer number (25029044274087).

Almost surely, 2^{100011233513533} is an apocalyptic number.

It is an amenable number.

100011233513533 is a deficient number, since it is larger than the sum of its proper divisors (104943582815).

100011233513533 is an equidigital number, since it uses as much as digits as its factorization.

100011233513533 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 104943582814.

The product of its (nonzero) digits is 12150, while the sum is 31.

Adding to 100011233513533 its reverse (335315332110001), we get a palindrome (435326565623534).

The spelling of 100011233513533 in words is "one hundred trillion, eleven billion, two hundred thirty-three million, five hundred thirteen thousand, five hundred thirty-three".