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100011403111 = 140877099553
BaseRepresentation
bin101110100100100100…
…1001110011101100111
3100120010222002200101011
41131021021032131213
53114310404344421
6113540011243051
710140242620504
oct1351111163547
9316128080334
10100011403111
1139461914464
1217471749487
13957aca2b49
144baa78c4ab
15290523d4e1
hex174924e767

100011403111 has 4 divisors (see below), whose sum is σ = 100018516752. Its totient is φ = 100004289472.

The previous prime is 100011403073. The next prime is 100011403153. The reversal of 100011403111 is 111304110001.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 100011403111 - 225 = 99977848679 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100011403091 and 100011403100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100011404111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3535690 + ... + 3563863.

It is an arithmetic number, because the mean of its divisors is an integer number (25004629188).

Almost surely, 2100011403111 is an apocalyptic number.

100011403111 is a deficient number, since it is larger than the sum of its proper divisors (7113641).

100011403111 is an equidigital number, since it uses as much as digits as its factorization.

100011403111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7113640.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 100011403111 its reverse (111304110001), we get a palindrome (211315513112).

The spelling of 100011403111 in words is "one hundred billion, eleven million, four hundred three thousand, one hundred eleven".

Divisors: 1 14087 7099553 100011403111