| Base | Representation |
|---|---|
| bin | 10110101111010111011100… |
| … | …011001010110010110000000 |
| 3 | 111010010001111000100122102000 |
| 4 | 112233113130121112112000 |
| 5 | 101102044044321320000 |
| 6 | 552412514510424000 |
| 7 | 30031425604031640 |
| oct | 2657273431262600 |
| 9 | 433101430318360 |
| 10 | 100012011120000 |
| 11 | 29959945a73431 |
| 12 | b272bb8202000 |
| 13 | 43a61276a2045 |
| 14 | 1a9a8700c6520 |
| 15 | b8681deda000 |
| hex | 5af5dc656580 |
100012011120000 has 1280 divisors, whose sum is σ = 421899638899200. Its totient is φ = 22840538112000.
The previous prime is 100012011119971. The next prime is 100012011120001. The reversal of 100012011120000 is 21110210001.
It is a happy number.
It is a Harshad number since it is a multiple of its sum of digits (9).
It is a super Niven number, because it is divisible the sum of any subset of its (nonzero) digits.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (100012011120001) by changing a digit.
It is a polite number, since it can be written in 159 ways as a sum of consecutive naturals, for example, 25598158047 + ... + 25598161953.
It is an arithmetic number, because the mean of its divisors is an integer number (329609092890).
Almost surely, 2100012011120000 is an apocalyptic number.
100012011120000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 100012011120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (210949819449600).
100012011120000 is an abundant number, since it is smaller than the sum of its proper divisors (321887627779200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
100012011120000 is an equidigital number, since it uses as much as digits as its factorization.
100012011120000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5650 (or 5617 counting only the distinct ones).
The product of its (nonzero) digits is 4, while the sum is 9.
Adding to 100012011120000 its reverse (21110210001), we get a palindrome (100033121330001).
Subtracting from 100012011120000 its reverse (21110210001), we obtain a palindrome (99990900909999).
The spelling of 100012011120000 in words is "one hundred trillion, twelve billion, eleven million, one hundred twenty thousand".
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