Base | Representation |
---|---|
bin | 10110101111010111011101… |
… | …000000001110101100101100 |
3 | 111010010001111201112110121121 |
4 | 112233113131000032230230 |
5 | 101102044104423443200 |
6 | 552412515513110324 |
7 | 30031426056462046 |
oct | 2657273500165454 |
9 | 433101451473547 |
10 | 100012021312300 |
11 | 299599507a5019 |
12 | b272bbb6b83a4 |
13 | 43a61298302a6 |
14 | 1a9a8715baa96 |
15 | b8681ed4ee1a |
hex | 5af5dd00eb2c |
100012021312300 has 144 divisors (see below), whose sum is σ = 218980254366720. Its totient is φ = 39646494720000.
The previous prime is 100012021312183. The next prime is 100012021312331. The reversal of 100012021312300 is 3213120210001.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 7128941686 + ... + 7128955714.
It is an arithmetic number, because the mean of its divisors is an integer number (1520696210880).
Almost surely, 2100012021312300 is an apocalyptic number.
100012021312300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
100012021312300 is an abundant number, since it is smaller than the sum of its proper divisors (118968233054420).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
100012021312300 is a wasteful number, since it uses less digits than its factorization.
100012021312300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15692 (or 15685 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 100012021312300 its reverse (3213120210001), we get a palindrome (103225141522301).
The spelling of 100012021312300 in words is "one hundred trillion, twelve billion, twenty-one million, three hundred twelve thousand, three hundred".
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