10001220012013 has 2 divisors, whose sum is σ = 10001220012014. Its totient is φ = 10001220012012.

The previous prime is 10001220012011. The next prime is 10001220012079. The reversal of 10001220012013 is 31021002210001.

10001220012013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5228297183209 + 4772922828804 = 2286547^2 + 2184702^2 .

It is a cyclic number.

It is not a de Polignac number, because 10001220012013 - 2¹ = 10001220012011 is a prime.

Together with 10001220012011, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 10001220011984 and 10001220012002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10001220012011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000610006006 + 5000610006007.

It is an arithmetic number, because the mean of its divisors is an integer number (5000610006007).

Almost surely, 2^{10001220012013} is an apocalyptic number.

It is an amenable number.

10001220012013 is a deficient number, since it is larger than the sum of its proper divisors (1).

10001220012013 is an equidigital number, since it uses as much as digits as its factorization.

10001220012013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 10001220012013 its reverse (31021002210001), we get a palindrome (41022222222014).

The spelling of 10001220012013 in words is "ten trillion, one billion, two hundred twenty million, twelve thousand, thirteen".